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4x^2+60x-616=0
a = 4; b = 60; c = -616;
Δ = b2-4ac
Δ = 602-4·4·(-616)
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13456}=116$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-116}{2*4}=\frac{-176}{8} =-22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+116}{2*4}=\frac{56}{8} =7 $
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